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谐响应分析四案例!

12月前浏览2033

谐响应分析


谐响应分析用于确定线性结构在承受随时间按正弦(简谐)规律变化的载荷时的稳态响应,分析过程中只计算结构的稳态受迫振动,不考虑激振开始时的瞬态振动。  

 

本文主要分享四个谐响应分析案例,看似简单,但只不过是模型简单,麻雀虽小五脏俱全,通过这四个案例完全可以掌握谐响应分析方法,以进一步针对自己的模型需求进行谐响应分析。

一般谐响应分析前需要进行模态求解,案例一至四的模态求解都是采用了Block Lanczos方法求解模态(ANTYPE,mode,案例一至四的主要不同在于其谐响应分析(ANTYPE,HARMONIC)过程中。

 
案例一:完全分析方法(HROPT,FULL)  ,施加位移激励进行扫频。  
案例二:模态叠加法,基于大质量法的加速度激励进行扫频,要知道,ANSYS软件进行谐响应分析时只能施加位移载荷、节点力载荷,无法施加加速度载荷,而且施加非零位移时只能用完全求解器求解这样不仅耗费计算资源,这里采用大质量法可以实现加速度载荷激励形式。  
案例三:与案例二的唯一区别是案例三的求解结果在自然频率区进行了密集计算,也就是说,在自然频率处,扫频步长更加密集。  
案例四:本案例求解设置与案例二相同,其突出亮点是可以自定义加速度载荷谱。也就是说,可以定义在不同频率施加不同的激励,也可以理解为谱分析。  

附件:命令流

1:

finish

/clear

/PREP7  

g=386.4            ! gravity in/sec^2

totg=1             ! load in g's

xa=g*totg          ! acceleration in/sec^2

pi=3.141592654     ! pi

/title,DIRECT DISPLACEMENT METHOD 

!!!!Pre-processing!!!!

RECTNG,20,,.25,, 

ET,1,PLANE42

UIMP,1,EX, , ,30e6, 

UIMP,1,NUXY, , ,.3, 

UIMP,1,DENS, , ,.000729,

LESIZE,2, , ,4, , , , ,1  

LESIZE,4, , ,4, , , , ,1  

LESIZE,1, , ,80, , , , ,1 

LESIZE,3, , ,80, , , , ,1 

MSHAPE,0,2D 

MSHKEY,1

AMESH,all   

nsel,s,loc,x,-10,.0001  

d,all,all,0

allsel,all

FINISH  

!!!!Solution Processing Modal Analysis!!!!

/SOLU   

ANTYPE,2

MODOPT,LANB,6   

EQSLV,SPAR  

MXPAND,6, , ,0  

MODOPT,LANB,6,0,0, ,OFF, ,0 

SOLVE   

FINISH  

!!!!Postprocess Modal Analysis!!!!

/POST1  

*GET,freq1,MODE,1,FREQ  

*GET,freq2,MODE,2,FREQ

*GET,freq3,MODE,3,FREQ

finish

!!!!Solution Process Full Harmonic Analysis!!!!

/solu

ANTYPE,3

HROPT,FULL  

HROUT,ON 

EQSLV,FRONT,0,     !波前求解器

DDELE,1,ALL  

nsel,s,loc,x,-10,.0001  

d,all,ux,0

d,all,uy,1

allsel,all

HARFRQ,freq2*.5,freq3*1.2, 

NSUBST,50, 

KBC,1     

DMPRAT,.0003,  

outres,all,all  

solve

finish

/POST26 

NSOL,2,83,U,Y,                     ! raw results

PROD,3,1,1, , , , ,2*pi,2*pi,1,    ! omega squared in radians

QUOT,4,2,3, , , , ,xa,1,           ! displacements: (raw results*accel)/omega^2

PROD,5,2, , , , , ,xa              ! accelerations: raw results*accel

PROD,6,2, , , , , ,xa/g            ! g's: (raw results*accel)/g

/eof

PLVAR,

案例2:

finish

/clear

/PREP7  

xm=1e5       ! mass for the large mass

g=386.4      ! acceration of gravity

totg=1       ! total number of g's applied to the model

xa=g*totg    ! acceleration applied to the model

xf=xm*xa     ! force required to applied desired acceleration f=ma

pi=3.141592654

/title,LARGE MASS METHOD ACCELERATION INPUT

RECTNG,20,,.25,, 

ET,1,PLANE42

UIMP,1,EX, , ,30e6, 

UIMP,1,NUXY, , ,.3, 

UIMP,1,DENS, , ,.000729,

LESIZE,2, , ,4, , , , ,1 

LESIZE,4, , ,4, , , , ,1  

LESIZE,1, , ,80, , , , ,1 

LESIZE,3, , ,80, , , , ,1 

MSHAPE,0,2D 

MSHKEY,1

AMESH,all   

numoff,node,100

!!!!Add large mass!!!

ET,2,MASS21 

KEYOPT,2,2,0

KEYOPT,2,3,0

R,2,1e5,1e5,1e5,1e5,1e5,1e5, 

n,1,-1   

type,2  

real,2  

mat,2   

e,1

nsel,s,loc,x,-1,0   

cerig,1,all,all,uxyz

allsel,all

numcmp,all 

FINISH  

!!!!MODAL ANALYSIS!!!!!!!!!!!!!!!!!!!!!!!

/SOLU   

ANTYPE,2

EQSLV,SPAR  

MXPAND,20, , ,0  

MODOPT,LANB,20,0,0, ,OFF, ,0   /! no shift get all rigid body modes

! this will allow the acceleration at the large mass to be calculated

! otherwise the acceleration at the large mass is incorrect

SOLVE   

FINISH  

!!!!HARMONIC ANALYSIS!!!!!!!!!!

/solu

ANTYPE,3

HROPT,MSUP,0, , 

HROUT,ON,OFF,0 

 EQSLV,FRONT,0,  

KBC,1   

DMPRAT,.03, 

outres,all,all  

f,1,fy,(xf)

harfrq,10,40

nsubst,25

solve

finish

!!!!POSTPROCESS TIME HISTORY!!!!!!!!!!!!!

/POST26 

file,,rfrq

NSOL,2,83,U,Y,                     !  node 83 displacement

PROD,4,1,1, , , , ,2*pi,2*pi,1,    ! omega squared

PROD,5,2,4, , , , ,1,1,1,          ! acceleration

PROD,6,5, , , , , ,1/g             ! results in g's

/AXLAB,X,Freqency   

/AXLAB,Y,Response in G  

/GROPT,LOGX,ON  

/GROPT,LOGY,OFF 

PLVAR,6

/eof

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Expansion results to .rst file!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

FINISH  

/SOLU   

EXPASS,1

NUMEXP,25,10,40,1  

HREXP,ALL,  

/STATUS,SOLU

SOLVE   

FINISH  

案例3:

finish

/clear

/PREP7  

xm=1e5       ! mass for the large mass

g=386.4      ! acceration of gravity

totg=1       ! total number of g's applied to the model

xa=g*totg    ! acceleration applied to the model

xf=xm*xa     ! force required to applied desired acceleration f=ma

pi=3.141592654

/title,LARGE MASS METHOD ACCELERATION INPUT

RECTNG,20,,.25,, 

ET,1,PLANE42

UIMP,1,EX, , ,30e6, 

UIMP,1,NUXY, , ,.3, 

UIMP,1,DENS, , ,.000729,

LESIZE,2, , ,4, , , , ,1 

LESIZE,4, , ,4, , , , ,1  

LESIZE,1, , ,80, , , , ,1 

LESIZE,3, , ,80, , , , ,1 

MSHAPE,0,2D 

MSHKEY,1

AMESH,all   

numoff,node,100

!!!!Add large mass!!!

ET,2,MASS21 

KEYOPT,2,2,0

KEYOPT,2,3,0

R,2,1e5,1e5,1e5,1e5,1e5,1e5, 

n,1,-1   

type,2  

real,2  

mat,2   

e,1

nsel,s,loc,x,-1,0   

cerig,1,all,all,uxyz

allsel,all

numcmp,all 

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

FINISH  

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!MODAL ANALYSIS!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

/SOLU   

ANTYPE,2

EQSLV,SPAR  

MXPAND,20, , ,0  

MODOPT,LANB,20,0,0, ,OFF, ,0   ! no shift get all rigid body modes

! this will allow the acceleration at the large mass to be calculated

! otherwise the acceleration at the large mass is incorrect

SOLVE   

FINISH  

/POST1  

finish

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!HARMONIC ANALYSIS!!!!!!!!!!!!!!!!!!!!!

/solu

ANTYPE,3

!*  

HROPT,MSUP,0, , 

HROUT,ON,OFF,0  EQSLV,FRONT,0,  

KBC,1   

DMPRAT,.03, 

outres,all,all  

f,1,fy,(xf)

harfrq,10,40

hrout,,on        ! turns cluster option on, ansys calculated freqs

nsubst,10        ! 1-10 default 4

solve

finish

!!!!POSTPROCESS TIME HISTORY!!!!!!!!!!!!!!!!!!!!!!

/POST26 

file,,rfrq

NSOL,2,83,U,Y,                     !  node 83 displacement

PROD,4,1,1, , , , ,2*pi,2*pi,1,    ! omega squared

PROD,5,2,4, , , , ,1,1,1,          ! acceleration

PROD,6,5, , , , , ,1/g             ! results in g's

/AXLAB,X,Freqency   

/AXLAB,Y,Response in G  

/GROPT,LOGX,ON  

/GROPT,LOGY,OFF 

PLVAR,6

/eof

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Expansion results to .rst file!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

FINISH  

/SOLU   

EXPASS,1

NUMEXP,25,10,40,1  

HREXP,ALL,  

!*  

/STATUS,SOLU

SOLVE   

FINISH  

案例4:

finish

/clear

/PREP7  

xm=1e5       ! mass for the large mass

g=386.4      ! acceration of gravity

totg=1       ! total number of g's applied to the model

xa=g*totg    ! acceleration applied to the model

xf=xm*xa     ! force required to applied desired acceleration f=ma

pi=3.141592654

/title,LARGE MASS METHOD ACCELERATION INPUT

RECTNG,20,,.25,, 

ET,1,PLANE42

UIMP,1,EX, , ,30e6, 

UIMP,1,NUXY, , ,.3, 

UIMP,1,DENS, , ,.000729,

LESIZE,2, , ,4, , , , ,1 

LESIZE,4, , ,4, , , , ,1  

LESIZE,1, , ,80, , , , ,1 

LESIZE,3, , ,80, , , , ,1 

MSHAPE,0,2D 

MSHKEY,1

AMESH,all   

numoff,node,100

!!!!Add large mass!!!

ET,2,MASS21 

KEYOPT,2,2,0

KEYOPT,2,3,0

R,2,1e5,1e5,1e5,1e5,1e5,1e5, 

n,1,-1   

type,2  

real,2  

mat,2   

e,1

nsel,s,loc,x,-1,0   

cerig,1,all,all,uxyz

allsel,all

numcmp,all 

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

FINISH  

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!MODAL ANALYSIS!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

/SOLU   

ANTYPE,2

EQSLV,SPAR  

MXPAND,6, , ,0  

MODOPT,LANB,6,1,0, ,OFF, ,0 

SOLVE   

FINISH  

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!HARMONIC ANALYSIS!!!!!!!!!!!!!!!!!!!!!

/solu

ANTYPE,3

HROPT,MSUP,0, , 

HROUT,ON,OFF,0  

EQSLV,FRONT,0,  

KBC,1   

DMPRAT,.03, 

outres,all,all  

!!!!FIRST SET OF FREQ AND LOAD!!!!

!!!!Parameters of sine sweep spec!!!!!!!!!!!!!!

bfreq1=5             ! begining freq

efreq1=50            ! endding freq

xload1=(.1*g)        ! acceleration of load

xoct1=.1             ! oct/time

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Determine how many frequency steps!!!!

cnt1=0

*do,i,1,50

  *if,i,ne,1,then

    dfreq=dfreq*(1+(xoct1*2))

  *endif

  *if,i,eq,1,then

    dfreq=bfreq1

  *endif

  *if,dfreq,lt,efreq1,then

    cnt1=cnt1+1

  *endif

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!dimension freq table col1=freq col2=load!!!!

*dim,freq1,table,cnt1,2

*VFILL,freq1(0,0),RAMP,0,1,

*do,i,1,2

 *VFILL,freq1(0,i),RAMP,i,1,

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Build freq table, load model, and solve!!!!!!

*do,i,1,cnt1

  *if,i,ne,1,then

    freq1(i,1)=freq1((i-1),1)*(1+(xoct1*2))

  *endif

  *if,i,eq,1,then

    freq1(i,1)=bfreq1

  *endif

  freq1(i,2)=xload1

  f,1,fy,(xm*xload1)

  harfrq,freq1(i,1),freq1(i,1)

  nsubst,1

  solve

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!SECOND SET OF FREQ AND LOAD!!!!

!!!!Parameters of sine sweep spec!!!!!!!!!!!!!!

bfreq2=50             ! begining freq

efreq2=200             ! endding freq

xload2=(.5*g)          ! acceleration of load

xoct2=.1              ! oct/time

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Determine how many frequency steps!!!!

cnt2=1

*do,i,1,50

  *if,i,ne,1,then

    dfreq=dfreq*(1+(xoct2*2))

  *endif

  *if,i,eq,1,then

    dfreq=bfreq2

  *endif

  *if,dfreq,lt,efreq2,then

    cnt2=cnt2+1

  *endif

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!dimension freq table col1=freq col2=load!!!!

*dim,freq2,table,cnt2,2

*VFILL,freq2(0,0),RAMP,0,1,

*do,i,1,2

 *VFILL,freq2(0,i),RAMP,i,1,

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Build freq table, load model, and solve!!!!!!

*do,i,1,cnt2

  *if,i,ne,1,then

    freq2(i,1)=freq2((i-1),1)*(1+(xoct2*2))

  *endif

  *if,i,eq,1,then

    freq2(i,1)=bfreq2

  *endif

  freq2(i,2)=xload2

  f,1,fy,(xm*xload2)

  harfrq,freq2(i,1),freq2(i,1)

  nsubst,1

  solve

*enddo

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

finish

!!!!POSTPROCESS TIME HISTORY!!!!!!!!!!!!!!!!!!!!!!

/POST26 

file,,rfrq

NSOL,2,83,U,Y,                     ! displacement

PROD,4,1,1, , , , ,2*pi,2*pi,1,    ! omega squared

PROD,5,2,4, , , , ,1,1,1,          ! acceleration

PROD,6,5, , , , , ,1/g             ! results in g's

 /eof

/AXLAB,X,Freqency  

/AXLAB,Y,Response in G  

/GROPT,LOGX,ON  

/GROPT,LOGY,OFF 

PLVAR,6

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!Expansion results to .rst file!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

FINISH  

/SOLU  

EXPASS,1

*do,i,1,cnt1 

  EXPSOL,,,freq1(i,1) ,1  

  HREXP,ALL,  

  SOLVE 

*enddo  

!!!!!!!!!!!!!!!!!!

*do,i,1,cnt2

  EXPSOL,,,freq2(i,1) ,1  

  HREXP,ALL,  

  SOLVE  

*enddo

finish

全文结束,感谢阅读。

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首次发布时间:2023-09-12
最近编辑:12月前
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